Let A and B be square matrices of the order 3 × 3. Is (AB)^2 = A^2 B^2 ? Give reasons. - Sarthaks eConnect | Largest Online Education Community
![inequality - How prove $\frac{a^2}{a+2b^2}+\frac{b^2}{b+2c^2}+\frac{c^2 }{c+2a^2}\ge 1$ - Mathematics Stack Exchange inequality - How prove $\frac{a^2}{a+2b^2}+\frac{b^2}{b+2c^2}+\frac{c^2 }{c+2a^2}\ge 1$ - Mathematics Stack Exchange](https://i.stack.imgur.com/OKG5E.jpg)
inequality - How prove $\frac{a^2}{a+2b^2}+\frac{b^2}{b+2c^2}+\frac{c^2 }{c+2a^2}\ge 1$ - Mathematics Stack Exchange
![a+b)^2-(a-b)^2 divided by a^2b-ab^2 - Maths - Algebraic Expressions and Identities - 12926957 | Meritnation.com a+b)^2-(a-b)^2 divided by a^2b-ab^2 - Maths - Algebraic Expressions and Identities - 12926957 | Meritnation.com](https://s3mn.mnimgs.com/img/shared/content_ck_images/ck_5b5d2e0bb8158.jpg)
a+b)^2-(a-b)^2 divided by a^2b-ab^2 - Maths - Algebraic Expressions and Identities - 12926957 | Meritnation.com
Using properties of determinants, prove the following: |(1+a^2-b^2,2ab,-2b ),(2ab,1-a^2+b^2,2a),(2b,-2a,1-a^2-b^2)|=(1+a^2+b^2)^3 - Sarthaks eConnect | Largest Online Education Community
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![1+a^(2)-b^(2),2ab,-2b),(2ab,1-a^(2)+b^(2),2a),(2b,-2a,1-a^(2)-b^(2)):}|=(1+a ^(2)+b^(2)).` - YouTube 1+a^(2)-b^(2),2ab,-2b),(2ab,1-a^(2)+b^(2),2a),(2b,-2a,1-a^(2)-b^(2)):}|=(1+a ^(2)+b^(2)).` - YouTube](https://i.ytimg.com/vi/v4iNkF7Ra9A/maxresdefault.jpg)
1+a^(2)-b^(2),2ab,-2b),(2ab,1-a^(2)+b^(2),2a),(2b,-2a,1-a^(2)-b^(2)):}|=(1+a ^(2)+b^(2)).` - YouTube
![Prove that (ab)^2=a^2b^2 where a,b∈G is an abelian group || Group Theory || Education Help #study - YouTube Prove that (ab)^2=a^2b^2 where a,b∈G is an abelian group || Group Theory || Education Help #study - YouTube](https://i.ytimg.com/vi/KcXlFlNcJHU/maxresdefault.jpg)